Can you please answer and explain question 13 Thank you 13
Can you please answer and explain question 13?
 Thank you! :)
 13. Aqueous s olutions of NaC and NauCrOs a solution of AgNO, is added (dropwise) At first, a white added, a yellow ollowing is the most accurate conclusion based on these results? are mised and they do not react. To this misture an aqueous solid begins to form. AgCHs) is white in color and Ag/Croalsh is vehow solid forms. As the AgNOs solution continues to be The molar solubility of the NacI is greater than the molar solubility of NaCrO, because the white solid of the Nac is less than the molar solubility of Na Cros because the white sblid solubility of A/CrOs because the white solid (n) The molar solubility formed first. (C) The molar solubility of Agal is greater than the molar (o) The meld first (D) The molar solubility of Agci is less than the molar solubility of AgcrO. because the white solid formed first 14. Barium lodate has a Ks of 4.0x 10. What is the lodate ion concentration in a saturated solution of barium iodate? 1.0 x 10M B) 2.0 x 10 M (C) 6.3 x 10s M (D) 2.0 x 10 M a (1e4) 15. Which of these salts would have increased solubility in a 0.10 M solution of HNOs, compared with their bilities in pure water at the same temperature? ) AgBr Mg(OH)2-7 (D) Pblz 16. When 0.10 mole of solid Ag:C:Os is added to 1 L of pure water at 25\'C, a saturated solution results. The solubility of Ag:C:Osis 2.1x 10 4M. Which would be the correct setup to calculate the Kup of Ag C0? (A) Ksp (2.1 x 10(2.1 x 104) BjKsp = (4.2 x 10-*)\"(2.1 x 10-4) K 1x10 021 10 4) (D) K,p = (2.1X 10\'4))2(21x104) 0.10 17. The Kip of a hypothetical metallic hydroxide, MOH is 1.0x 10*. What is the pH of a saturated solution of MOH? B) 8.00 (D) 12.00 · 4.00 10.00 pot Solution
13) For the mentioned reaction we can see AgCl 1st precipitate out as white ppt. Chloride ion have higher affinity for Ag cation and thus in laboratory AgNO3 is used for detection of Chloride ions. Hence we can see NaCl have higher molar solublity than Na2CrO4 thus option A is correct option
Thus answer is A

