Given A412 B83 Find line perpendicular to AB Use ymxb formSo

Given: A(4,12) B(-8,-3)

Find line perpendicular to AB

Use y=mx+b form

Points are A(4,12),B(-8,-3)

Slope is ,m=(-3-12)/(-8-4)=5/4

Therefore slope of line perpendicular to AB is -4/5

And y=m x+b

12=(-4/5)(4)+b

12=-16/5+b

b=76/5

Hence the required equation is

y= (-4/5)x+76/5