lastd pter 9 Solids and Fluids 1200 httpwwwwebassignnetwebSt

last?d… pter 9- Solids and Fluids (1200) http:/www.webassign.net/web/Student/Assignment-Responses/la 7. -i pointsSerCP9 9.P.028.WI. Piston in the figure below has a diameter of 0.29 im; Piston has a diameter of 1.3 in. In the absence of friction, determine the force F necessary to support the 500-lb weight. lb 500 2 2.0 in. 10 in. Need Help? Watchlt_ : Talk to a Tutor 8.-/1 pointsSerCP9 9.P.031

Solution

Consider two things -

I - The pressures on the pistons,

II - And the torque due to the force applied on the lever.

Again,

Sum of the torques = 0
Sum of the pressures = 0

The pivot point is at poiston 2.

Let R1 be the distance from the pivot to F (12\")
Let R2 be the distance from the pivot to piston 1 (2\")

R1F = R2F1

where F1 is the net force on piston 1

Sum of the pressures = 0 implies that

P2 = P1

F2/A2 = F1/A1

(500)/(1.3)² = F1/(0.29)²

=> F1 = 24.88 N

So,

F = (R2/R1)F1 = (2/12)(24.88) = 4.15 N

I hope, I am solving the problem in correct way.