Homework SourseFind the length of the curve y 3x216 on the interval 02Solut
Find the length of the curve y= 3x^2-16 on the interval [0,2].
Solution
the length of the curve y= 3x^2-16
l=int√(1+dy/dx^2)dx
l=int√(1+36x^2)dx
l=(1+36x^2)^3/2[x+13x^3]/3/2
applying limits 0 to 2
l=11.642*1091=1271.407
l=1271.407-0=1271.407m
![Find the length of the curve y= 3x^2-16 on the interval [0,2].Solution the length of the curve y= 3x^2-16 l=int√(1+dy/dx^2)dx l=int√(1+36x^2)](/WebImages/37/find-the-length-of-the-curve-y-3x216-on-the-interval-02solut-1110039-1761588391-0.webp "Find the length of the curve y= 3x^2-16 on the interval [0,2].Solution the length of the curve y= 3x^2-16 l=int√(1+dy/dx^2)dx l=int√(1+36x^2)")
