Na Cl2 NaCl 1 write the balanced equation for this reactio

Na + Cl2 ---> NaCl

(1) write the balanced equation for this reaction

(2) how many moles of NaCl can you make if you have 0.1 moles of Na and an unlimited amount of Cl2?

(3) how many moles of NaCl can you make if you have 0.1 moles of Cl2 and an unlimited amount of Na?

(4) how many moles of NaCl can you make if you have 0.1 moles of Cl2 and 0.1 moles of Na?

(5) The girl scouts sell 200 million boxes of cookies per year. Assuming one batch of cookies will fill 6 boxes and you need 1 teaspoon of table salt (NaCl) to make a batch of cookies, how many grams of Na and Cl2 will you need to make enough salt for one year of girl scout cookies? 1 teaspoon of salt weighs 3.8 grams.

Solution

1) 2Na (s) + Cl2(g) ---------------> 2 NaCl(s)

2) From the equation

2 moles of Na gives 2 moles of NaCl

Thus 0.1 mol of Na gives 0.1 mol of NaCl

3) From the equation

1 mol of Cl2 gives 2 moles of NaCl

Thus 0.1 mol of Cl2 gives 0.2 moles of NaCl

4)

2Na (s) + Cl2(g) ---------------> 2 NaCl(s)

0.1 0.1 0 initial moles

0 0.05 0.1 after reations

Thus Na is the limiting reagent and we get 0.1 moles of NaCl

5) 1 easppon = 3.8 g of NaCl = 6 boxes

Thus for 6 boxes of cookies 3.8g of NaCl is needed

200x10⁶ boxes need = 200x10⁶ x 3.8/6

= 126.67x10⁶ g

moles of NaCl required = mass/ molar mass

=126.67x10⁶ g /58.5g/mol

= 2.165x10⁶ mol

To make 2.165x10⁶ mol of NaCl ,

we need sodium ,Na =2.165x10⁶ mol

and clorine ,Cl2 = 2.165x10⁶ mol/2

=1.083 x10⁶ mol

Mass of Na needed = moles x atomic mass

=2.165x10⁶ mol x 23g/mol

=4.98x10⁷ g of Na

mass of Cl2 needed = [2.165x10⁶ mol /2] x71g/mol

= 7.687 x10⁷ g of chlorine