Use the given zero to find the remaining zeros of the polyno
Use the given zero to find the remaining zeros of the polynomial function. (Enter you P(x) = X^4 - 6x^3 + 47X^2 - 98x + 290; 2 + 5i
Solution
P(x) = x^4 - 6x^3 + 47 x^2 - 98x + 290
one zero is 2+5i
since complex zeros occur in pairs other zero would be 2 - 5i
( x - (2+5i)) ( x-(2-5i)) = x^2 - 4x +29
dividing the polynomial by x^2 - 4x +29
x^4 - 6x^3 + 47 x^2 - 98x + 290 / x^2 - 4x +29 = x^2 - 2x +10
setting x^2 - 2x +10 =0 and solving for x
x = 1-3i
x = 1+ 3i
remaining zeros are
x = 2 - 5i , 1+3i , 1-3i
