Consider a tungsten wire sigma 18e7 with a cross sectional

Consider a tungsten wire sigma = 1.8e7 with a cross sectional area of 1 square millimeter and carrying 0.3 amperes of current. Calculate the strength of the very small electric field required to drive this current through the wire. 0.0243 V/m 0.0167 V/m 0.540 V/m 0.0083 V/m

Solution

Here ,

sigma = 1.8 *10^7

area, A = 1 mm^2 = 1 *10^-6 m^2

I = 0.3 A

J = sigma * Electric

I/Area = sigma * electric field

0.3/(1 *10^-6) = 1.8 *10^7 * electric field

electric field = 0.0167 V/m

the electric field is 0.0167 V/m