A random sample of 42 gas grills has a mean price of 62840 a

A random sample of 42 gas grills has a mean price of $628.40 and a standard deviation is $58.10.

The 90% confidence interval is ____,_____

The 95% confidence interval is ____,_____

which interval is wider the 95% or 90% confidence interval

Solution

n = 42

Mean = 628.40

std dev = 58.10

Std error = 58.10/rt 41

Margin of error for 90% = 1.64 times std error