The point charges in the figure below have the following val

The point charges in the figure below have the following values: q1 = +2.2 µC, q2 = +5.5 µC, q3 = -0.89 µC. (Let the +x-axis point to the right.)

(A) force on q1 due to q3:

F31 = ( k q1 q3 / d^2) (i)

force on q1 due to q2:

F21 = (k q1 q2 / d^2) (-cos60i - sin60j)

Fnet = ( kq1q3/d^2 - kq1q2 cos60 /d^2)i - (k q1 q2 sin60 / d^2) j

k q1 q3/d^2 = 9.31 N

k q1 q2 / d^2 = 57.55 N

Fnet = (9.31 - 57.55cos60 i - 57.55sin60 j

Fnet = - 19.47 i - 49.8j

magnitude = sqrt(19.47^2 + 49.8^2) = 53.5 N ......Ans

@ = 180 + tan^-1(49.8 / 19.47) =248.65 deg

(B) now d is doubled then

k q1 q3/d^2 = 2.33 N

k q1 q2 / d^2 = 14.4 N

Fnet = (2.33 - 14.4cos60)i - 14.4sin60 j

Fnet = - 4.87 i - 12.47 j N

magnitude = sqrt(4.87^2 + 12.47^2) = 13.4 N ......Ans

@ = 180 + tan^-1(12.47 /4.87) =248.65 deg