Write the reaction and find the Rate Law for the reaction of

Write the reaction and find the Rate Law for the reaction of hydrogen and lodine that produces hydrogen iodide. Find the value of the rate constant for this reaction. 1. Reaction: Experiment Initial Rate (M/s) Initial [H2], M Initial [2], M 1 1.9x10230.01130.0011 0.0033 0.0011 0.0056 1.1x10-22 9.3x1023 1.9x10-22 0.0220 0.0550 0.0220 3 4 Rate Law Value of k

Solution

Let the rate ( R)= k[H2]^m [I2]ⁿ, where m and n are orders of reaction with respect to [H2] and [I2] respectively. K is the rate constant.

From experiment-1

K(0.0113)^m* (0.0011)ⁿ = 1.9*10^-23   (1)

From experiment-3

K*(0.0550)^m*(0.0011)ⁿ= 9.3*10^-23 (2)

Eq.2/eq.1, (0.055/0.0113)^m= 9.3/1.9=4.9

4.9^m= 4.9, m=1

From experiment-2

K(0.022)^m* (0.0033)ⁿ = 1.1*10^-22   (2)

From experiment-4

K*0.022)^m *(0.0056)ⁿ= 1.9*10-22 (4)

Eq.4/Eq.2 (0.0056/0.0033) ⁿ= 1.9/1.1

Hence n=1

Hence the rate law becomes

R= K[H2][I2]

From experiment-1

1.9*10^-23= K*0.0113*0.0011

K= 1.53*10^-18/M.sec, the rate law becomes = 1.53*10^-18[H2][I2]