When an electron moves from A to B along an electric field l

When an electron moves from A to B along an electric field line in the figure, the electric field does 4.81 times 10^-19 J of work on it. Calculate the following electric potential differences: (i) V_B - V_A (ii) V_C - V_B

Solution

a)

i)We know that work done on the charge = q(Vb-Va)

so Vb-Va = W/q = 4.81*10^-19/(1.6*10^-19)=3.006V

ii)Vc = Vb because both lie on an equipotential line so their potential are equal.

So Vc-Vb = Vb-Va = 3.006V