solution to question C pls Diagnostic Problem 3 Make sure th
 solution to question C pls
Solution
Please find the answers below:
According to the information, the cross between blue and black beetle yeilds all black beetles in F1 generation. This means that black phenotype is dominant over blue. Further, since all the beetles are black in color, they should be all heterozygous/homozyous in nature. However, they cannot be homozyous in nature because in that case a gene for black color must be obtained from other parent which would make it black. Thus, the genotypes must be homozygous for both the parents i.e.:
Blue beetle : bb
Black beetle: BB
Thus, the offsprings will have:
Phenotype: All black
Genotype: All Bb
Part b: Thus, for part b of the question it can be seen that there has been conducted a cross where blue and black beetles have been crossed to yield an almost 1:1 ratio of both beetles. This suggests that this is a test cross where the F1 individual or Bb has been crossed with homozygous recessive individual from parent generation i.e. bb.
Part C: As it can be seen in part b, the genotype of black beetle is Bb and blue beetle is bb. Thus, the cross would be:
Genotype: bb: Bb :: 1:1
Phenotype: Blue : black :: 1:1
| B | b | |
| b | Bb | bb | 
| b | Bb | bb | 

