Determine the value of the turnover number of the enzyme cat

Determine the value of the turnover number of the enzyme catalase, given that Rmax (Vmax) for catalase = 41 mmol·L–1·s–1 and [E]t = 1.4 nmol·L–1. Catalase has a single active site.

Determine the value of the turnover number of the enzyme catalase, given that Rmax(Vax) for catalase mmoI.L-1, s-1 and [E-= 1.4 nmol. L-1, Catalase has a single active site. 41 Number 13.22 x 106

Solution

given

Vmax = 41 mmol L-1 s-1 = 41 x 10-3 mol L-1 s-1

[E]t = 1.4 nmol L-1 = 1.4 x 10-9 mol L-1

now

by definition

turnover number = Vmax / [E]t

turnover number = (41 x 10-3 x mol L-1 s-1 ) / (1.4 x 10-9 mol L-1)

turnover number = 2.9286 x 10⁷ s-1