how much heat is needed to raise the temperature of 910 g of

how much heat is needed to raise the temperature of 91.0 g of water from 26C to 93C?

I calculated the answer as (91.0g)(4.18J/g)(67C)= 25485.46J but it is wrong.

Solution

dT = 93-26 = 67 C

C = 4.18 J/g-C

m = 91 g

1 = m*C*dT = 91*4.187*67 = 25528.139J = 25.528139 KJ