MasteringCherristry Homework Chapter 15 Goegle Chrome a Secu

MasteringCherristry: Homework Chapter 15 Goegle Chrome a Secure httpsfsession.masteringchemistry.com/myct itemView?a Type here to search 4@ 283532D18 ^

Solution

Part A)

T = 57+273.15 => 330.15 K, R = 0.08206 L.atm/mol.K

Kp = 30.8 (0.08206 * 330.15)^-2

Kp = 4.19*10^-2

Part B)

T = 285 + 273.15 => 558.15 K

Kc = Kp /(RT) ^n

Kc = 0.0135 / (0.08206*558.15)^-2

Kc = 28.3