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     owLv2] Online teachin × +  eastce agen we om irntakeAssignment takeCo alentActiv tydllocatoriassignment-take&takeAssignmentsess; onto ator- pr Use the Refereaces to access insportant values if needed for this question. pt In the laboratory you are asked to make a 0.369 m calcium nitrate solution using 255 grams of water. of calcium nitrate should you add? grams How 1 pt 1 pt Submit Answer Try Another Version 1 itern attempt remaining 1 pr 1 pt ![owLv2] Online teachin × + eastce agen we om irntakeAssignment takeCo alentActiv tydllocatoriassignment-take&takeAssignmentsess; onto ator- pr Use the Refer  owLv2] Online teachin × + eastce agen we om irntakeAssignment takeCo alentActiv tydllocatoriassignment-take&takeAssignmentsess; onto ator- pr Use the Refer](/WebImages/37/owlv2-online-teachin-eastce-agen-we-om-irntakeassignment-t-1111190-1761589228-0.webp) 
  
  Solution
Answer:
Molality of solution (m) = # of moles of Solute (n) / Mass of solvent in Kg (M).
m = n/M
Given: m = 0.369 m, Mass of solvent water = 255 g = 0.255 Kg. n = ?
Rearranging above equation (1) for n we get,
n = mM
n = 0.369*0.255 =
n = 0.0941 moles.
# of moles of Calcium Nitrate = 0.0941 moles.
Now from # of Moles, one can find corresponding mass using the Molar mass of that compound.
Mass of Calcium nitrate = 164.088 g/mole,
Formula:
Mass of Calcium nitrate = # of moles of Calcium nitrate * Molar mass
= 0.0941*164.088
= 15.440 g
15.440 g of Calcium Nitrate should be added.
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