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owLv2] Online teachin × + eastce agen we om irntakeAssignment takeCo alentActiv tydllocatoriassignment-take&takeAssignmentsess; onto ator- pr Use the Refereaces to access insportant values if needed for this question. pt In the laboratory you are asked to make a 0.369 m calcium nitrate solution using 255 grams of water. of calcium nitrate should you add? grams How 1 pt 1 pt Submit Answer Try Another Version 1 itern attempt remaining 1 pr 1 pt

Solution

Answer:

Molality of solution (m) = # of moles of Solute (n) / Mass of solvent in Kg (M).

m = n/M

Given: m = 0.369 m, Mass of solvent water = 255 g = 0.255 Kg. n = ?

Rearranging above equation (1) for n we get,

n = mM

n = 0.369*0.255 =

n = 0.0941 moles.

# of moles of Calcium Nitrate = 0.0941 moles.

Now from # of Moles, one can find corresponding mass using the Molar mass of that compound.

Mass of Calcium nitrate = 164.088 g/mole,

Formula:

Mass of Calcium nitrate = # of moles of Calcium nitrate * Molar mass

= 0.0941*164.088

= 15.440 g

15.440 g of Calcium Nitrate should be added.

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