Solve the equation on the interval 02 tan theta 1sec theta 1

Solve the equation on the interval [0,2).

(tan theta +1)(sec theta +1)= 0

theta =

Solution

(tan theta +1)(sec theta +1)= 0

(tan theta +1)= 0, (sec theta +1)= 0

(tan theta =-1), (sec theta =-1)

theta=3_/4,7_/4;

theta=3_/4,,7_/4