Determine the values of the specific properties for each of

Determine the values of the specific properties for each of the following conditions: R-134 at P = 4 Bars and T = 22.5 degree C find the specific volume v = m^3/kg H_2O at p = 100 Ibf/in^2 and v = 1.5 ft^3/lb find the temperature T = degree F H_2O at p = 175 bar and T = 140 degree C find the internal energy u = kJ/kg R-22 at P = 10 Bars and T = 10 degree C find the specific volume v = m^3/kg Ammonia at 0 degree C at x = 0.10 find specific internal energy u = kJ/kg H_2Oat p = 5 bar and T = 160 degree C find the specific volume v = m^3/kg

Solution

R134 at p= 4 bar, T= 22.5 0c we get

Using ideal gas equation PV= NRT

N= 1 mole

R= 8.314 J/MOL*K

T=22.5+273=295.5

P= 400000 PASCAL

V= NRT/P = 1*8.314*295.5/400000 = 0.00614196 M3

SPECIFIC VOLUME= 0.00614 M3/KG .......TAKING MASS= 1 KG

2....

T= PV/NR = 689476*0.0936419/1*8.314

T= 776.56 K = 938.138 F

3..........

CHANGE IN INETRNEL ENERGY

U= TS-PV

4......

V= NRT/P = 1*8.314*283/1000000 = 0.00235286 M3/KG...AT 1 KG MASSS

5.....

U= TS-PV

6.....

V= NRT/P = 1*8.314*433/500000= 0.0071999 M3

AT M= 1 KG

SPECIFIC VOLUME V= 0.0071999 M3/KG