3x2 5x 4 lesserthanequalto 7x2 16 The solution is Type yo

3/x^2 - 5x + 4 lesserthanequalto 7/x^2 - 16 The solution is (Type your answer in interval notation Use integers or fractions for any numbers in the expression Type an exact answer using radicals as needed)

Solution

3/x²-5x+4<7/x²-16

Multiplying both sides by( x²-5x+4)(x²-16),we get

3(x²-16)<7(x²-5x+4)

3x²-48<7x²-35x+28

4x²-35x+76>0

(x-4)(4x-19)>0

(x-4)(x-4.75)>0

x should be (-infinity,0) (4.7 5,infinity)