Solve sinx 052 on 2pi lessthanorequalto x SolutionSolution

Solve sin(x) = 0.52 on - 2pi lessthanorequalto x

Solution

Solution:

sinx = 0.52, [-2, 2)

Rationlize equation

sinx = 13/25

Solution in range [-2, 2)

x = - - arcsin(13/25) = - - 0.547 = -3.688 rad

x = - arcsin(13/25) = - 0.547 = 2.594 rad

x = arcsin(13/25) = 0.547 rad

x = arcsin(13/25) - 2 = 0.547 - 2 = -5.736