A mass attached to a spring oscillates with a period of 315
A mass attached to a spring oscillates with a period of 3.15 s.
(a) If the mass starts from rest at x = 0.0480 m and time t = 0, where is it at time t = 6.51 s?
Solution
Angular velocity of shm = 360º/3.15 s
= 113.2º/s
Amplitude of shm, A = 0.048 m
Displacement x is given by,
x = A*cos(t)
x = 0.048 * cos(113.2* 6.51)º
x = 0.048 * cos (736.932)
x = - 0.0108739 m
