Suppose we have a 350 L sample containing 80 moles of ozone

Suppose we have a 3.50 L sample containing .80 moles of ozone gas, O3, at a pressure of 1.55 atm and a temperature of 298K. If all of this O3 is converted to oxygen, O2, at the same temperature and pressure then what will be the volume of the oxygen formed?

Solution

2O3 ---> 3O2

since P R and T are constant

so V/n = RT/P = constant

hence

V1/n1 = V2/n2

now 2 moles O3 give 3 mle O2 so 0.8 mole O3 gives 0.8*3/2 = 1.2 moles O2

3.5/0.8 = V2/1.2

V2 = 5.25 L.................ANS