Find solution for log log x log x2 log 10x Find X and corr

Find solution for log
log x + log (x-2) = log (10x)
Find X and correct to four decimal places

Solution

logx + log(x-2) = log(10x)
or log(x(x-2))=log(10x).............................(1)
or x(x-2)=10x
or x2-12x=0

or x(x-12)=0

or x=0 or x=12

x cant be 0 because log(0) does not exist as in (1)

So,x=12

Find solution for log log x + log (x-2) = log (10x) Find X and correct to four decimal placesSolutionlogx + log(x-2) = log(10x) or log(x(x-2))=log(10x).........

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