Find solution for log log x log x2 log 10x Find X and corr
Find solution for log
log x + log (x-2) = log (10x)
Find X and correct to four decimal places
log x + log (x-2) = log (10x)
Find X and correct to four decimal places
Solution
logx + log(x-2) = log(10x)
or log(x(x-2))=log(10x).............................(1)
or x(x-2)=10x
or x2-12x=0
or x(x-12)=0
or x=0 or x=12
x cant be 0 because log(0) does not exist as in (1)
So,x=12
