The lengths of a shadow cast by a vertical gnomonic a drives
Solution
s = h(sin(90 - theta)/sintheta
= hcos(theta)/sintheta
= hcot(theta)
h = 5ft
s = 5cot(theta)
theta = 15 ; s = 18.66
theta = 30 deg ; s = 8.66
theta = 45 deg ; s = 5
theta = 75 deg ; s = 1.339
theta = 90 deg ; s = 0
maximum shadow ; s = 18.66 ; theta = 18.66 deg
minimum shadow ; s = 0 ; theta = 0
