Write a program with c only to implement a simple currency c

Write a program (with c only) to implement a simple currency converter program. Commands are as follows:

Euro-US

US-Euro

Euro-Pound

Pound-Euro

Pound-US

US-Pound

showrates

quit

Note that the commands are EXACTLY as shown. Capital letters and lower case letters as shown. There is a very good reason for this requirement, as will become clear later in the semester.

Commands work as follows:

Euro-US

requests a currency amount in Euros

converts that into a currency amount in $US.

US-Euro

reverse the above; request an amount in $US, convert it into Euros

Euro-Pound, Pound-Euro

same thing for converting Pound Sterling to Euros and vice versa

Pound-US, US-Pound

same thing for converting Pound Sterling to $US and vice versa

showrates

shows the exchange rates used in an appropriate way

quit

exit the program

Use the following currency exchange rates (taken from Monday, August 26, 2013)

$1.0000 US = 0.74759 Euro

$1.0000 US = 0.64173 Pound Sterling

Solution

Following code will give you the desired functionality:

//rate conversion
#include<stdio.h>
#include<stdlib.h>

//prototype declaration

int main()
{
int menu;
float dollar, euro, pound;
printf(\"Choose among the following commands\ \");
printf(\"1. Euro-US\ \");
printf(\"2. US-Euro\ \");
printf(\"3. Euro-Pound\ \");
printf(\"4. Pound-Euro\ \");
printf(\"5. Pound-US\ \");
printf(\"6. US-Pound\ \");
printf(\"7. show rates\ \");
printf(\"8. quit\ \");
scanf(\"%d\",&menu);
switch(menu)
{
case 1:
printf(\"Enter amount in Euro: \");
scanf(\"%f\",&euro);
dollar =(1/0.74759) * euro;
printf(\"%f Euro will be equal to %f Dollars\ \",euro,dollar);
break;
case 2:
printf(\"Enter amount in Dollars: \");
scanf(\"%f\",&dollar);
euro = 0.74759 * dollar;
printf(\"%f Dollars will be equal to %f Euro\ \",dollar,euro);
break;
case 3:
printf(\"Enter amount in Euro: \");
scanf(\"%f\",&euro);
pound = 0.85839 *euro;
printf(\"%f Euro will be equal to %f Pound Sterling\ \",euro,pound);
break;
case 4:
printf(\"Enter amount in Pound Sterling: \");
scanf(\"%f\",&pound);
euro = 1.16496 *pound;
printf(\"%f Pound Sterling will be equal to %f Euro\ \",pound,euro);
break;
case 5:
printf(\"Enter amount in Dollars: \");
scanf(\"%f\",&dollar);
pound = 0.64173 * dollar;
printf(\"%f Dollars will be equal to %f Pound Sterling\ \",dollar,pound);
break;
case 6:
printf(\"Enter amount in Pounds: \");
scanf(\"%f\",&pound);
dollar = 1.55828 *pound;
printf(\"%f Pounds will be equal to %f Dollars\ \",pound,dollar);
break;
case 7:
printf(\"$1 US = 0.74759 Euro\ \");
printf(\"1 Euro = $1.3376 US\ \");
printf(\"1 Euro = 0.85839 Pound Sterling\ \");
printf(\"1 Pound Sterling = 1.16496 Euro\ \");
printf(\"$1 US = 0.64173 Pound Sterling\ \");
printf(\"1 Pound Sterling = $1.55828 US\ \");
break;
case 8:
exit(1);
default:
printf(\"Wrong choice\ \");
}//end of switch case
return 0;
}//end of main function

Hope it helps. Do comment your feedback. Thanks.