Homework SourseI need to solve the following using the elementary row trans
I need to solve the following using the elementary row transformations of matrix A if one exists:
A=
I need to find A-1
| 5 | 7 | -6 |
| 12 | 2 | 1 |
| 7 | -5 | 7 |
Solution
Your matrix
Eliminate elements in the 1st column under the 1st element
Eliminate elements in the 2nd column under the 2nd element
Multiply the main diagonal elements
5 x (-74/5) x 0 = 0
solution
Determinant is 0
Determinant is zero, therefore inverse matrix doesn\'t exist
| Sign | A1 | A2 | A3 | |
|---|---|---|---|---|
| + | 1 | 5 | 7 | -6 |
| 2 | 12 | 2 | 1 | |
| 3 | 7 | -5 | 7 |
