a ns s 15 pointal The domain of 2 ad ts ranes domain b 2f3 S

a. ns s 15 pointal The domain of )-2 ad ts ranes domain (b) 2f(+3)

Solution

-5 <= x <= 2
-1 <= y <= 6

a) f(x/2) - 1

With f(x/2), we get domain to be : -10 <= x <= 4

And since that is being subtracted by 1, we get range :
-2 <= y <= 5

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b)
2f(x + 3) :

f(x+3) means moving left by 3

So, Domain :
-8 <= x <= -1

And since we are multiplyjng by 2,
range is :
-2 <= y <= 12

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c)
-f(-x) :

With -f(-x),
both domain and range flip over

Domain :
-2 <= x <= 5

Range :
-6 <= y <= 1