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Predict the number of unpaired electrons and LFSE in Delta for each of the following situations: Octahedral low-spin d6 ion: Octahedral high-spin d6 ion [CO(H2O)6](ClO4)2 K3[Fe(CN)6]Solution
unpaired electron=0 and LFSE= -24 DELTA
unpaired electron=4, LFSE= -4 DELTA
unpaired electron=3, LFSE= -8 DELTA
unpaired electron=1, LFSE= -20 DELTA
