A piston cylinder device contains 12lbm of H2O at 500 psia a

A piston cylinder device contains 12lbm of H2O at 500 psia and 400oF. The tank is heated in an isobaric process until the temperature reaches 720oF. Determine the final internal energy and the change in volume of the H2O.

Solution

W=P*(T2-T1)=500*(177.78)=88890

Q=mc*(T2-T1)=12*4185.5*177.78=8929178.28

Change in internal energy=8929178.28-88890=8040.288 kj.