For the following exercises consider a stone tossed into the

For the following exercises, consider a stone tossed into the air from ground level with an initial velocity of 15 m/sec. Its height in meters at time t seconds is h(t) = 15t - 4.9t^2. [T] Compute the average velocity of the stone over the given time intervals. [1, 1.05| [1, 1 01] [1, 1.005] [1, 1.0011 Use the preceding exercise to guess the instantaneous velocity of the stone at t = 1 sec.

Solution

Here\' answer to Qns:

a) Average velocity is total height travelled /total time = (15(1.05)-4.9*(1.05)^2) - (15*1-4.9*1^2) / (1.05-1) = 4.955

b) 5.151

c) 5.1755

d) 5.1951

19. Inst, velocity is dh/dt at 1 sec. So, differentiate the eqn, dh/dt= 15-9.8*t = 15-9.8(1) = 5.2 m/sec