Item 6 Youve just isolated a new dominant mutation of the te

Item 6 Youve just isolated a new dominant mutation of the testy (ty) gene in the spotted snigglewiggle. You suspect that your new allele is a hypermorph, so youve tentatively notated itas tyh: you\'re anxious to confirm this functional assignment. Other ty alleles have already been fully characterized: the null allele, tyo, a partial-loss-offunction allele, tyypo, and a neomorphic allele, tyvoo. However, no hypermorphic allele had been described previously, so you\'re very excited. Using both wild-type and tyH flies, you\'ve been successful in generating flies with small chromosomal duplications that include either wild-type or tyH. Part A What two genotypes could you use to compare phenotypes to provide definitive identification of tyH as a hypermorphic mutation, rather than any other kind of dominant allele? Select all that apply. ty compared to ty ry o ty compared to ty My O ty try ty\" compared to ty try M ty ryht compared to tyHny O tytyHry compared to tytry My Answers Give Up Submit Part B You did it! You demonstrated genetically that tyH isa hypermorph. So, what would the most ikely phenotypic result be for the ty ny genotype? O The phenol of tyttyo will most likely be more severe e. less wild-type) than the phenotype of ty nyt type O The pheno of tytty will most likely be the same as the phenotype of ty O The phenotype of tyHry will most likely be less severe e. closer to wild-type) than the phenotype of tyhy Submit My Answers Give Up

Solution

A) Hyper morph mutation cause an increase in normal gene function. The alleles are dominant gain of function. The phenotype of Hyper morph is worsened by increasing the gene dose of the wild type. So answer is: ty^H ty⁺ ty⁺ to ty^H ty⁺

B) The Phenotype ty^H ty⁰ will be more likely severe than the Phenotype ty^H ty⁺

C) The gene dose of the wild type is increased, so ty^H ty⁺ ty⁺ is worsened compared to ty^H ty⁺

D) The third drawing.