3 How many moles of hydrogen is present in 386 mL of H colle
Solution
Answer :- n = 0.00151 mole of H2
The vapor pressure of the water in the collecting vessel is 23.8 torr
Since the total pressure is the atmospheric pressure
The pressure due to the hydrogen is,
748.0 - 23.8 = 724.2 torr
Since you are given volume, pressure, and temperature, you can use the ideal gas law
PV = nRT
Where,
P = the pressure
V = the volume
n = the number of moles
R = the universal gas constant
T = the temperature
to solve for n, the number of moles of gas.
The universal gas constant, R, is usually given as
R=0.082atmL / molK
Which means that you will have to convert the pressure of the gas from torr to atm by using the conversion factor
1 atm = 760 torr
So, plug in your values and solve for n
n = PV / RT
n = ((724.2/760) × 0.0386L) / (( 0.082atm.L/ mol.k)(273 + 25)
n = 0.00151 mole of H2
