6ab please and thank u 6 Use the Law of Cosines to find the
6a-b please and thank u
Solution
6 a)
applying law of cosines
b^2 = a^2 + c^2 - 2ac cos (B)
plugging the values
b^2 = 10.5^2 + 9.5^2 - 2(10.5)(9.5) cos 40
b = 6.9
therefore length of AC = 6.9 cm
b) again applying law of cosines
e^2 = f^2 + d^2 - 2fd cos 75
e^2 = 13^2 + 11^2 - 2(13)(11) cos 75
e = 14.7 cm
4a) applying law of sines to find the value of x
a / sin A = b/ sin B
90/ sin 90 = x / sin 50
90 / 1 = x / sin 50
x = 90 * sin 50
x = 68.94 mm
b) again applying law of sines
x / sin 51 = 30 / sin 39
x = 30/ sin 39 * sin 51
x = 37.05 cm
