log 2x log 4x log 128 log 2x log 4x log 128 log 2x log
log 2x + log 4x = log 128
log 2x + log 4x = log 128
log 2x + log 4x = log 128
Solution
log 2x + log 4x =log 128
=> log ( 2x * 4x ) = log 128
=> 2x * 4x = 128 [ remove log in both sides ]
=> 8x^2 = 128
=> x^2 = 16
=> x = 4 ( answer )
