The lengths of time in minutes that 10 patients waited in a

The lengths of time, in minutes, that 10 patients waited in a doctor\'s office before receiving treatment were recorded as follows: 5, 11, 9, 5, 10, 15, 6, 10, 5, and 10. Treating the data as a random sample, find the mean, range, and standard deviation.

Solution

mean = the sum of the values divided by the number of values = 86/10 = 8.6

The Range is the difference between the lowest and highest values = {5,15}

Standard Deviation (SD) is the measure of spread of the numbers in a set of data from its mean value. It is also called as SD and is represented using the symbol (sigma). This can also be said as a measure of variability or volatility in the given set of data

standard deviation=3.30656

 The lengths of time, in minutes, that 10 patients waited in a doctor\'s office before receiving treatment were recorded as follows: 5, 11, 9, 5, 10, 15, 6, 10,

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