2 A chemical procedure requires 500 g of a 125 wt AgNO3 aque
Solution
Ans. Given, [AgNO3] = 12.5 % (w/w)
Required amount of solution = 500.0 g
#a. A 12.5 % (w/w) means that there is 12.5 g solute per 100.0 g solution.
Required mass of pure AgNO3 = w/w % [AgNO3] x Mass of solution
= (12.5 g AgNO3 / 100 g solution) x 500 g solution
= 62.5 g AgNO3
Therefore, required mass of AgNO3 = 62.5 g
#b. Let the required mass of impure sample = X
So,
84.2 % of X = 62.5 g
Or, X = 62.5 g / 0.842
Hence, X = 74.228 g
Therefore, required mass of impure sample = 74.23 g
# Required mass of water (solvent) = Total mass of solution – Mass of solute
= 500.0 g – 74.23 g
= 425.77 g
