Write the output which is generated from each of the followi
Solution
Initially, result=0 and i=1
as i=1 it will enter in the do-while loop and there is no case statement for i=1, so it default case will be executed.
now i=1 and result=0+1=1. so in screen it will print i=1 and result=1.
note that while loop condition is using post increment operator.it means i will be compared first with old value and it will get incremented value next time. that is after first iteration comparison will be 1<3 like that and i will be incrmented to 2 .
for next iteration i=2 :
matched with case 2: so result=result-2=1-2=-1
as there is no break statement all of the cases below case 2 will be executed till it gets break statement.so case 3 and default case will be executed.
after case 3 executed : result=result*3=(-1)*3 = -3
after default case executed: result=result+1 = -3 +1 =-2
now i=2 and result=-2 will be printed for cout statement.
next condition check for while loop will be like this 2<3 and i will be incremented to 3.
for next iteration i=3:
this time case 3 and default case will be executed .
after case 3 executed : result=result*3=(-2)*3 = -6
after default case executed: result=result+1 = -6 +1 =-5
so i=3 and result=-5 will be printed.
after this condition check will be failed as 3< 3 this fails.It will come out of the loop.
