sjccengagenowcom oWLv2I Online teaching and learning resourc

sjc.cengagenow.com oWLv2I Online teaching and learning resource from Cengage Learning Review Topics] Use the References to access important values if needed for this question. A 3.27 gram sample of an unknown gas is found to occupy a volume of 1.71 L at a pressure of 607 mmHg and a temperature of 43 °C. Assume ideal behavior The molar mass of the unknown gas is g/mol. Submit Answer Retry Entire Group 8 more group attempts remaining Previous Next

Solution

PV = nRT

n = mass (g) / molar mass(g/mol)

Molar mass = mass (g) * R * T / ( P * V)

R = 0.08206 L.atm/mol.K

T = 43 + 273.15 => 316.15 K

P = 607 / 760 => 0.7987 atm

V = 1.71 L

Molar mass = 3.27 g * 0.08206 L.atm/mol.K* 316.15 K / (0.7987 atm * 1.71 L)

Molar mass = 62.11 g/mol