e2x2exSolutionWe have e2x 2ex Let ex a Then a2 2a or a2

e^(2x)=2e^(x)

Solution

We have e2x = 2ex . Let ex = a. Then, a2 = 2a or a2 -2a = 0 or a(a -2 ) = 0. Thus either a = 0 or a = 2.

When ex = 0 , then x = - . Also, when ex = 2, we have, on taking natural logarithm of both the sides, x ln e = ln 2 or, x = ln 2 ( as ln e = 1) or x = 0.693147718 (approximately) = 0.69 ( on rounding off to 2 decimal places).

e^(2x)=2e^(x)SolutionWe have e2x = 2ex . Let ex = a. Then, a2 = 2a or a2 -2a = 0 or a(a -2 ) = 0. Thus either a = 0 or a = 2. When ex = 0 , then x = - . Also, w

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