The area of a circular sector is determined by 12 square The

.The area of a circular sector is determined by 1/2 square. The rear wiper of a car rotates 125 ° and clears a distance of 35.6 centimeters determines the area covered by rl cleaner.

.Determines the 6 trigonometric functions of the angle of the next point (-4 / 5, -3 / 5)

sen angulo
cos angulo
tan angulo
sec angulo
csc angulo
cot angulo

Solution

A = 1/2
theta = 125 deg
L = arc length= 35.6 cm

Now, we have L = theta/360 * 2pi * r

35.6 = 125/360 * 2pi * r

35.6 = 2.181661564992912r

r = 16.317838 cm

Now, using this, we find area...

A = theta/360 * pi * r^2

A = (125/360) * pi * 16.317838^2

A = 290.4575 sq cm

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(-4/5 , -3/5)

A quick look will tell that the hypotenuse is 1

So, we have these....
x = -4/5
y = -3/5
r = 1

sin = y/r = -3/5

cos = x/r = -4/5

tan(angle) = y/x = (-3/5) / (-4/5)
tan = 3/4

csc = -5/3

sec = -5/4

cot = 4/3