Given the set S A B C D E how many ways are there to a sele
Solution
Answers:
a) Total letters in S are 5 .
selecting 2 letters from S when repetitions allowed is 52 = 5x5 = 25
b) selecting 2 letters from S when repetition is not allowed is combination of 5 things taken 2 at a time i.e. 5C2
= 5!/ 2!3! = 5x4/2 = 10
c) Total letters in S are 5 .
selecting 3 letters from S when repetitions allowed is 53 = 5x5x5 = 125
d) Selecting 2 letters from S such that first letter is different from second :
First letter is A and second letter is any one of remainig four OR First letter is B and second letter is any one of remainig four OR First letter is C and second letter is any one of remainig four OR First letter is D and second letter is any one of remainig four OR First letter is E and second letter is any one of remainig four
therefore 4C1 + 4C1 +4C1 +4C1 +4C1 = 5.4C1 = 5.4!/3! = 5.4 = 20
e) Select three letters from S such that no two letters are same:
First letter is A and second letter maybe any of four remaing letters and third may be any of remaning three letters.
In this way we have 5 possibilities possible .
Therefore total is = 5(4C1.3C1) = 5.4.3 = 60
