What is the energy released in this nuclear reaction What is

What is the energy released in this nuclear reaction?

What is the energy released in this nuclear reaction 19 9F + 4 2He rightarrow Ne + 1 1H? (The atomic mass of 19F is 18.998403 u. and that of 22Ne is 21.991385 u)

Solution

Energy released = m*c^2

Where m = difference in the mass of products and reactants

C is the speed of light

m = (21.991385+1.00794)-(4.002602+18.998403)

m = 0.00168u

Energy released in 1u = 931MeV

Total energy released = 0.00168*931= 1.56407MeV