Homework SourseWe are finding intervals of concavity of fx x4 4x3 18x2 W
We are finding intervals of concavity of f(x) = x4 - 4x3 - 18x2
We now know f \'\'(x) = 12x2 - 24x - 36
Now find the possible inflection points of f;
that is, the points where f \'\' is zero or does not exist.
Inflection Point Candidate List:
We now know f \'\'(x) = 12x2 - 24x - 36
Now find the possible inflection points of f;
that is, the points where f \'\' is zero or does not exist.
Inflection Point Candidate List:
Solution
to find the inflection pt, f\"(x) = 0 , so 12x^2-24x-36 = 0 12(x^2-2x-3) = 0 ==> 12(x+1)(x-3) = 0 x = -1, 3 iflection pt
