Homework SourseA ball is thrown upwards with an initial speed of 32 ft per
A ball is thrown upwards with an initial speed of 32 ft per second from 48 ft above the ground level.
1) how long does it take for the ball to hit the ground
2) what is the speed of the ball at impact
3) what is the maximum height of the ball (assume acceleration due to gravity is -32 ft/sec2
Note: let s(t) = the height of the ball at any time t
(height in feet and time in seconds)
Hint: find s(t) if s^(t)=-32, s\'(0)=32 and s(0) = 48
1) how long does it take for the ball to hit the ground
2) what is the speed of the ball at impact
3) what is the maximum height of the ball (assume acceleration due to gravity is -32 ft/sec2
Note: let s(t) = the height of the ball at any time t
(height in feet and time in seconds)
Hint: find s(t) if s^(t)=-32, s\'(0)=32 and s(0) = 48
Solution
h = ut + 0.5gt^2 -48 = 32t - 0.5*32*t^2 16t^2-32t-48 = 0 t = 3seconds v = u+at v = 32-32*3 = -64ft/s, speed = 64ft/s max height = 48+32^2/2*32 = 64ft
