D Question 25 1 pts Increasing the ultimate BOD in a stream
Solution
Answer 25:
Since L0 is the total amount of organic matter oxidised, so higher the BOD, higher the L0. This implies that statement number 5 is correct and 7 is wrong.
If we differentiate the Streeter-Phelps equation and pt it equal to zero, we get equation for critical time (Time to reach minimum dissolved oxygen). From that equation we can see that higher the L0 (or ultimate BOD), lesser the critical time. This implies that statement number 1 is correct and 2 is wrong.
k1 and k2 both depend only on temperature and not on BOD, so both the statements 3 &4 are wrong.
Since higher the L0, higher the critical oxygen deficit, hence lower the critical DO level, statement number 6 is correct and 8 and 9 are wrong.
Answer 26:
The first statement that BOD is first order reaction is CORRECT, and that reaction is given mathematically as dCt / dt = -kCt or Ct = C0e-kt or ln(Ct/C0) = -kt . So, Statements 1, 2, and 3 are CORRECT but statements 4, 6, 7, 8, and 9 are WRONG.
Half life is the time in which concentration becomes half for a first order reaction, i.e. Ct = 0.5C0. Hence Statement number 5 is WRONG.
