Find the value for the total moles of ions released when 88

Find the value for the total moles of ions released when 88 mL of 1.75M magnesium chloride dissolves completely in water.

magnesium chloride dissolves completely in water

It gives a cation of magnesium (Mg2+) and two anions of cloride (Cl-).

Moles of MgCl2 = molarity x volume

= 1.75 moles/L x 0.088 L

= 0.154 moles

MgCl2 = Mg2+ + 2Cl-

From the stoichiometry of the reaction

1 mol of MgCl2 gives = 2 mol of Cl-

0.154 moles of MgCl2 gives =2*0.154 = 0.308 moles of Cl-

1 mol of MgCl2 gives = 1 mol of Mg2+

0.154 moles of MgCl2 gives =0.154 moles of Mg2+

Total Moles of ions = 0.154 + 0.308 = 0.462 mol