What Volume of a 0345 M hydroiodic acid solution is required

What Volume of a 0.345 M hydroiodic acid solution is required to neutralize 22.8ml of 0.167 M calcium Hydroxide solution?

Balanced chemical equation is:
Ca(OH)2 + 2 HI ---> CaI2 + 2 H2O

Here:
M(Ca(OH)2)=0.167 M
M(HI)=0.345 M
V(Ca(OH)2)=22.8 mL

According to balanced reaction:
2*number of mol of Ca(OH)2 =1*number of mol of HI
2*M(Ca(OH)2)*V(Ca(OH)2) =1*M(HI)*V(HI)
2*0.167 M *22.8 mL = 1*0.345M *V(HI)
V(HI) = 22.1 mL

Answer: 22.1 mL