Given triangle ABC with alpha 40 degree beta 110 degree an

Given: triangle ABC with alpha = 40 degree, beta = 110 degree and b = 95. What is a ? What is c?

Solution

Alpha=40°,beta=110°,gamma=180-alpha-beta=30degree

b=95

Sin B/b=Sin alpha/a

Sin 110/95=sin 40/a

a=65

Sin beta/b=Sin gamma/c

Sin 110/95=sin 30/c

c=50.5