If A is singular then AB is also singular A B are both n tim

If A is singular then AB is also singular A, B are both n times n matrices

Solution

Given A is a singular matrix then

det(A)=0

Also given that A and B are square matrices of order n

By the properties of determinant det(AB) =det(A) det(B)

Since det(A) =0

det(AB)=0*det(B)

det(AB) =0

Therefore if A is singular then ABC is also singular